/*

 * Copyright (c) 2017, Oracle and/or its affiliates. All rights reserved.

 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.

 *

 * This code is free software; you can redistribute it and/or modify it

 * under the terms of the GNU General Public License version 2 only, as

 * published by the Free Software Foundation.

 *

 * This code is distributed in the hope that it will be useful, but WITHOUT

 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or

 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License

 * version 2 for more details (a copy is included in the LICENSE file that

 * accompanied this code).

 *

 * You should have received a copy of the GNU General Public License version

 * 2 along with this work; if not, write to the Free Software Foundation,

 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.

 *

 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA

 * or visit www.oracle.com if you need additional information or have any

 * questions.

 */

/*

 * @test

 * @bug 8186654

 * @summary Transpositions of an array result in the same

 *          EqualByteArray.hashCode()

 * @modules java.base/sun.security.util

 */

import sun.security.util.Cache;

public class EbaHash {

    public static void main(String[] args) throws Throwable {

        int h1 = new Cache.EqualByteArray(new byte[] {1,2,3}).hashCode();

        int h2 = new Cache.EqualByteArray(new byte[] {2,3,1}).hashCode();

        int h3 = new Cache.EqualByteArray(new byte[] {3,1,2}).hashCode();

        if (h1 == h2 && h2 == h3) {

            throw new RuntimeException("Transpositions of an array" +

                " resulted in the same hashCode()");

        }

    }

}