/*

 * Copyright (c) 1999, Oracle and/or its affiliates. All rights reserved.

 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.

 *

 * This code is free software; you can redistribute it and/or modify it

 * under the terms of the GNU General Public License version 2 only, as

 * published by the Free Software Foundation.

 *

 * This code is distributed in the hope that it will be useful, but WITHOUT

 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or

 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License

 * version 2 for more details (a copy is included in the LICENSE file that

 * accompanied this code).

 *

 * You should have received a copy of the GNU General Public License version

 * 2 along with this work; if not, write to the Free Software Foundation,

 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.

 *

 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA

 * or visit www.oracle.com if you need additional information or have any

 * questions.

 */

/*

 * @test

 * @bug 4252490

 * @summary The firstKey and lastKey

 */

import java.util.*;

public class SubMap {

    public static void main(String args[]) throws Exception {

        SortedMap m = new TreeMap();

        m.put(new Integer(1), new Integer(1));

        m.put(new Integer(2), new Integer(2));

        m.put(new Integer(3), new Integer(3));

        SortedMap m2 = m.subMap(new Integer(2), new Integer(2));

        boolean exc = false;

        try {

            m2.firstKey();

        } catch(NoSuchElementException e) {

            exc = true;

        }

        if (!exc)

            throw new Exception("first key");

        exc = false;

        try {

            m2.lastKey();

        } catch(NoSuchElementException e) {

            exc = true;

        }

        if (!exc)

            throw new Exception("last key");

        SortedMap m3 = m.subMap(new Integer(2), new Integer(3));

        if (!m3.firstKey().equals(new Integer(2)))

            throw new Exception("first key wrong");

        if (!m3.lastKey().equals(new Integer(2)))

            throw new Exception("last key wrong");

        SortedSet s = new TreeSet();

        s.add(new Integer(1));

        s.add(new Integer(2));

        s.add(new Integer(3));

        SortedSet s2 = s.subSet(new Integer(2), new Integer(2));

        exc = false;

        try {

            s2.first();

        } catch(NoSuchElementException e) {

            exc = true;

        }

        if (!exc)

            throw new Exception("first element");

        exc = false;

        try {

            s2.last();

        } catch(NoSuchElementException e) {

            exc = true;

        }

        if (!exc)

            throw new Exception("last element");

        SortedSet s3 = s.subSet(new Integer(2), new Integer(3));

        if (!s3.first().equals(new Integer(2)))

            throw new Exception("first element wrong");

        if (!s3.last().equals(new Integer(2)))

            throw new Exception("last element wrong");

    }

}