/*

 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.

 *

 * This code is free software; you can redistribute it and/or modify it

 * under the terms of the GNU General Public License version 2 only, as

 * published by the Free Software Foundation.

 *

 * This code is distributed in the hope that it will be useful, but WITHOUT

 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or

 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License

 * version 2 for more details (a copy is included in the LICENSE file that

 * accompanied this code).

 *

 * You should have received a copy of the GNU General Public License version

 * 2 along with this work; if not, write to the Free Software Foundation,

 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.

 *

 */

/*

 * @test

 * @bug 4350863 4358130

 * @summary Verify that name of superclass constructor exception can be

 * resolved correctly when instantiating a subclass.

 * @author maddox

 *

 * @compile SuperclassConstructorException.java

 */

class Superclass {

  public Superclass() throws java.io.IOException {}

}

class Subclass extends SuperclassConstructorException {}

class SuperclassConstructorException {

  public static void main(String args[]) {

    try {

      Object x = new Superclass(){};

      Object y = new Subclass();

    } catch (java.io.IOException e) {};

  }

}