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 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
 *
 * This code is free software; you can redistribute it and/or modify it
 * under the terms of the GNU General Public License version 2 only, as
 * published by the Free Software Foundation.
 *
 * This code is distributed in the hope that it will be useful, but WITHOUT
 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
 * version 2 for more details (a copy is included in the LICENSE file that
 * accompanied this code).
 *
 * You should have received a copy of the GNU General Public License version
 * 2 along with this work; if not, write to the Free Software Foundation,
 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
 *
 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
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 */

/*
 * @test
 * @bug 8072909
 * @run main/othervm -Xmx385m TimSortStackSize2 67108864
 * not for regular execution on all platforms:
 * run main/othervm -Xmx8g TimSortStackSize2 1073741824
 * run main/othervm -Xmx16g TimSortStackSize2 2147483644
 * @summary Test TimSort stack size on big arrays
 */
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Comparator;
import java.util.List;

public class TimSortStackSize2 {

    public static void main(String[] args) {
        int lengthOfTest = Integer.parseInt(args[0]);
        boolean passed = true;
        try {
            Integer [] a = new TimSortStackSize2(lengthOfTest).createArray();
            long begin = System.nanoTime();
            Arrays.sort(a, new Comparator<Object>() {
                    @SuppressWarnings("unchecked")
                    public int compare(Object first, Object second) {
                        return ((Comparable<Object>)first).compareTo(second);
                    }
                });
            long end = System.nanoTime();
            System.out.println("TimSort: " + (end - begin));
            a = null;
        } catch (ArrayIndexOutOfBoundsException e){
            System.out.println("TimSort broken:");
            e.printStackTrace();
            passed = false;
        }

        try {
            Integer [] a = new TimSortStackSize2(lengthOfTest).createArray();
            long begin = System.nanoTime();
            Arrays.sort(a);
            long end = System.nanoTime();
            System.out.println("ComparableTimSort: " + (end - begin));
            a = null;
        } catch (ArrayIndexOutOfBoundsException e){
            System.out.println("ComparableTimSort broken:");
            e.printStackTrace();
            passed = false;
        }
        if ( !passed ){
            throw new RuntimeException();
        }
    }

    private static final int MIN_MERGE = 32;
    private final int minRun;
    private final int length;
    private final List<Long> runs = new ArrayList<Long>();

    public TimSortStackSize2(int len) {
        this.length = len;
        minRun = minRunLength(len);
        fillRunsJDKWorstCase();
    }

    private static int minRunLength(int n) {
        assert n >= 0;
        int r = 0;      // Becomes 1 if any 1 bits are shifted off
        while (n >= MIN_MERGE) {
            r |= (n & 1);
            n >>= 1;
        }
        return n + r;
    }

    /**
     * Adds a sequence x_1, ..., x_n of run lengths to <code>runs</code> such that:<br>
     * 1. X = x_1 + ... + x_n <br>
     * 2. x_j >= minRun for all j <br>
     * 3. x_1 + ... + x_{j-2}  <  x_j  <  x_1 + ... + x_{j-1} for all j <br>
     * These conditions guarantee that TimSort merges all x_j's one by one
     * (resulting in X) using only merges on the second-to-last element.
     * @param X  The sum of the sequence that should be added to runs.
     */
    private void generateJDKWrongElem(long X) {
        for(long newTotal; X >= 2*minRun+1; X = newTotal) {
            //Default strategy
            newTotal = X/2 + 1;
            //Specialized strategies
            if(3*minRun+3 <= X && X <= 4*minRun+1) {
                // add x_1=MIN+1, x_2=MIN, x_3=X-newTotal  to runs
                newTotal = 2*minRun+1;
            } else if(5*minRun+5 <= X && X <= 6*minRun+5) {
                // add x_1=MIN+1, x_2=MIN, x_3=MIN+2, x_4=X-newTotal  to runs
                newTotal = 3*minRun+3;
            } else if(8*minRun+9 <= X && X <= 10*minRun+9) {
                // add x_1=MIN+1, x_2=MIN, x_3=MIN+2, x_4=2MIN+2, x_5=X-newTotal  to runs
                newTotal = 5*minRun+5;
            } else if(13*minRun+15 <= X && X <= 16*minRun+17) {
                // add x_1=MIN+1, x_2=MIN, x_3=MIN+2, x_4=2MIN+2, x_5=3MIN+4, x_6=X-newTotal  to runs
                newTotal = 8*minRun+9;
            }
            runs.add(0, X-newTotal);
        }
        runs.add(0, X);
    }

    /**
     * Fills <code>runs</code> with a sequence of run lengths of the form<br>
     * Y_n     x_{n,1}   x_{n,2}   ... x_{n,l_n} <br>
     * Y_{n-1} x_{n-1,1} x_{n-1,2} ... x_{n-1,l_{n-1}} <br>
     * ... <br>
     * Y_1     x_{1,1}   x_{1,2}   ... x_{1,l_1}<br>
     * The Y_i's are chosen to satisfy the invariant throughout execution,
     * but the x_{i,j}'s are merged (by <code>TimSort.mergeCollapse</code>)
     * into an X_i that violates the invariant.
     * X is the sum of all run lengths that will be added to <code>runs</code>.
     */
    private void fillRunsJDKWorstCase() {
        long runningTotal = 0;
        long Y = minRun + 4;
        long X = minRun;

        while(runningTotal+Y+X <= length) {
            runningTotal += X + Y;
            generateJDKWrongElem(X);
            runs.add(0,Y);

            // X_{i+1} = Y_i + x_{i,1} + 1, since runs.get(1) = x_{i,1}
            X = Y + runs.get(1) + 1;

            // Y_{i+1} = X_{i+1} + Y_i + 1
            Y += X + 1;
        }

        if(runningTotal + X <= length) {
            runningTotal += X;
            generateJDKWrongElem(X);
        }

        runs.add(length-runningTotal);
    }

    private Integer[] createArray() {
        Integer[] a = new Integer[length];
        Arrays.fill(a, 0);
        int endRun = -1;
        for(long len : runs)
            a[endRun+=len] = 1;
        a[length-1]=0;
        return a;
    }

}