--- a/jdk/src/java.base/share/classes/java/util/Arrays.java Wed Nov 04 12:46:05 2015 +0100
+++ b/jdk/src/java.base/share/classes/java/util/Arrays.java Wed Nov 04 16:44:38 2015 +0100
@@ -25,6 +25,8 @@
package java.util;
+import jdk.internal.HotSpotIntrinsicCandidate;
+
import java.lang.reflect.Array;
import java.util.concurrent.ForkJoinPool;
import java.util.function.BinaryOperator;
@@ -42,7 +44,6 @@
import java.util.stream.LongStream;
import java.util.stream.Stream;
import java.util.stream.StreamSupport;
-import jdk.internal.HotSpotIntrinsicCandidate;
/**
* This class contains various methods for manipulating arrays (such as
@@ -2586,6 +2587,55 @@
}
/**
+ * Returns true if the two specified arrays of longs, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static boolean equals(long[] a, int aFromIndex, int aToIndex,
+ long[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++)
+ if (a[aFromIndex++] != b[bFromIndex++])
+ return false;
+
+ return true;
+ }
+
+ /**
* Returns {@code true} if the two specified arrays of ints are
* <i>equal</i> to one another. Two arrays are considered equal if both
* arrays contain the same number of elements, and all corresponding pairs
@@ -2615,6 +2665,55 @@
}
/**
+ * Returns true if the two specified arrays of ints, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static boolean equals(int[] a, int aFromIndex, int aToIndex,
+ int[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++)
+ if (a[aFromIndex++] != b[bFromIndex++])
+ return false;
+
+ return true;
+ }
+
+ /**
* Returns {@code true} if the two specified arrays of shorts are
* <i>equal</i> to one another. Two arrays are considered equal if both
* arrays contain the same number of elements, and all corresponding pairs
@@ -2644,6 +2743,55 @@
}
/**
+ * Returns true if the two specified arrays of shorts, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static boolean equals(short[] a, int aFromIndex, int aToIndex,
+ short[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++)
+ if (a[aFromIndex++] != b[bFromIndex++])
+ return false;
+
+ return true;
+ }
+
+ /**
* Returns {@code true} if the two specified arrays of chars are
* <i>equal</i> to one another. Two arrays are considered equal if both
* arrays contain the same number of elements, and all corresponding pairs
@@ -2674,6 +2822,55 @@
}
/**
+ * Returns true if the two specified arrays of chars, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static boolean equals(char[] a, int aFromIndex, int aToIndex,
+ char[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++)
+ if (a[aFromIndex++] != b[bFromIndex++])
+ return false;
+
+ return true;
+ }
+
+ /**
* Returns {@code true} if the two specified arrays of bytes are
* <i>equal</i> to one another. Two arrays are considered equal if both
* arrays contain the same number of elements, and all corresponding pairs
@@ -2703,6 +2900,55 @@
}
/**
+ * Returns true if the two specified arrays of bytes, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static boolean equals(byte[] a, int aFromIndex, int aToIndex,
+ byte[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++)
+ if (a[aFromIndex++] != b[bFromIndex++])
+ return false;
+
+ return true;
+ }
+
+ /**
* Returns {@code true} if the two specified arrays of booleans are
* <i>equal</i> to one another. Two arrays are considered equal if both
* arrays contain the same number of elements, and all corresponding pairs
@@ -2732,6 +2978,55 @@
}
/**
+ * Returns true if the two specified arrays of booleans, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static boolean equals(boolean[] a, int aFromIndex, int aToIndex,
+ boolean[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++)
+ if (a[aFromIndex++] != b[bFromIndex++])
+ return false;
+
+ return true;
+ }
+
+ /**
* Returns {@code true} if the two specified arrays of doubles are
* <i>equal</i> to one another. Two arrays are considered equal if both
* arrays contain the same number of elements, and all corresponding pairs
@@ -2759,9 +3054,70 @@
if (a2.length != length)
return false;
- for (int i=0; i<length; i++)
- if (Double.doubleToLongBits(a[i])!=Double.doubleToLongBits(a2[i]))
- return false;
+ for (int i=0; i<length; i++) {
+ double v1 = a[i], v2 = a2[i];
+ if (Double.doubleToRawLongBits(v1) != Double.doubleToRawLongBits(v2))
+ if (!Double.isNaN(v1) || !Double.isNaN(v2))
+ return false;
+ }
+
+ return true;
+ }
+
+ /**
+ * Returns true if the two specified arrays of doubles, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * <p>Two doubles {@code d1} and {@code d2} are considered equal if:
+ * <pre> {@code new Double(d1).equals(new Double(d2))}</pre>
+ * (Unlike the {@code ==} operator, this method considers
+ * {@code NaN} equals to itself, and 0.0d unequal to -0.0d.)
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @see Double#equals(Object)
+ * @since 9
+ */
+ public static boolean equals(double[] a, int aFromIndex, int aToIndex,
+ double[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++) {
+ Double va = a[aFromIndex++], vb = b[bFromIndex++];
+ if (Double.doubleToRawLongBits(va) != Double.doubleToRawLongBits(vb))
+ if (!Double.isNaN(va) || !Double.isNaN(vb))
+ return false;
+ }
return true;
}
@@ -2794,9 +3150,70 @@
if (a2.length != length)
return false;
- for (int i=0; i<length; i++)
- if (Float.floatToIntBits(a[i])!=Float.floatToIntBits(a2[i]))
- return false;
+ for (int i=0; i<length; i++) {
+ float v1 = a[i], v2 = a2[i];
+ if (Float.floatToRawIntBits(v1) != Float.floatToRawIntBits(v2))
+ if (!Float.isNaN(v1) || !Float.isNaN(v2))
+ return false;
+ }
+
+ return true;
+ }
+
+ /**
+ * Returns true if the two specified arrays of floats, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * <p>Two floats {@code f1} and {@code f2} are considered equal if:
+ * <pre> {@code new Float(f1).equals(new Float(f2))}</pre>
+ * (Unlike the {@code ==} operator, this method considers
+ * {@code NaN} equals to itself, and 0.0f unequal to -0.0f.)
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @see Float#equals(Object)
+ * @since 9
+ */
+ public static boolean equals(float[] a, int aFromIndex, int aToIndex,
+ float[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++) {
+ float va = a[aFromIndex++], vb = b[bFromIndex++];
+ if (Float.floatToRawIntBits(va) != Float.floatToRawIntBits(vb))
+ if (!Float.isNaN(va) || !Float.isNaN(vb))
+ return false;
+ }
return true;
}
@@ -2827,9 +3244,60 @@
return false;
for (int i=0; i<length; i++) {
- Object o1 = a[i];
- Object o2 = a2[i];
- if (!(o1==null ? o2==null : o1.equals(o2)))
+ if (!Objects.equals(a[i], a2[i]))
+ return false;
+ }
+
+ return true;
+ }
+
+ /**
+ * Returns true if the two specified arrays of Objects, over the specified
+ * ranges, are <i>equal</i> to one another.
+ *
+ * <p>Two arrays are considered equal if the number of elements covered by
+ * each range is the same, and all corresponding pairs of elements over the
+ * specified ranges in the two arrays are equal. In other words, two arrays
+ * are equal if they contain, over the specified ranges, the same elements
+ * in the same order.
+ *
+ * <p>Two objects {@code e1} and {@code e2} are considered <i>equal</i> if
+ * {@code Objects.equals(e1, e2)}.
+ *
+ * @param a the first array to be tested for equality
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested fro equality
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return {@code true} if the two arrays, over the specified ranges, are
+ * equal
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static boolean equals(Object[] a, int aFromIndex, int aToIndex,
+ Object[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ if (aLength != bLength)
+ return false;
+
+ for (int i = 0; i < aLength; i++) {
+ if (!Objects.equals(a[aFromIndex++], b[bFromIndex++]))
return false;
}
@@ -5185,4 +5653,3233 @@
public static DoubleStream stream(double[] array, int startInclusive, int endExclusive) {
return StreamSupport.doubleStream(spliterator(array, startInclusive, endExclusive), false);
}
-}
+
+
+ // Comparison methods
+
+ // Compare boolean
+
+ /**
+ * Compares two {@code boolean} arrays lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Boolean#compare(boolean, boolean)}, at an index within the
+ * respective arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(boolean[], boolean[])} for the definition of a
+ * common and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(boolean[], boolean[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Boolean.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compare(boolean[] a, boolean[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Boolean.compare(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code boolean} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Boolean#compare(boolean, boolean)}, at a
+ * relative index within the respective arrays that is the length of the
+ * prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(boolean[], int, int, boolean[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(boolean[], int, int, boolean[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Boolean.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int compare(boolean[] a, int aFromIndex, int aToIndex,
+ boolean[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ boolean va = a[aFromIndex++];
+ boolean vb = b[bFromIndex++];
+ if (va != vb) return Boolean.compare(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ // Compare byte
+
+ /**
+ * Compares two {@code byte} arrays lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Byte#compare(byte, byte)}, at an index within the respective
+ * arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(byte[], byte[])} for the definition of a common and
+ * proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(byte[], byte[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Byte.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compare(byte[] a, byte[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Byte.compare(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code byte} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Byte#compare(byte, byte)}, at a relative index
+ * within the respective arrays that is the length of the prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(byte[], int, int, byte[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(byte[], int, int, byte[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Byte.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int compare(byte[] a, int aFromIndex, int aToIndex,
+ byte[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ byte va = a[aFromIndex++];
+ byte vb = b[bFromIndex++];
+ if (va != vb) return Byte.compare(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ /**
+ * Compares two {@code byte} arrays lexicographically, numerically treating
+ * elements as unsigned.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Byte#compareUnsigned(byte, byte)}, at an index within the
+ * respective arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(byte[], byte[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Byte.compareUnsigned(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are
+ * equal and contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compareUnsigned(byte[] a, byte[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Byte.compareUnsigned(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+
+ /**
+ * Compares two {@code byte} arrays lexicographically over the specified
+ * ranges, numerically treating elements as unsigned.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Byte#compareUnsigned(byte, byte)}, at a
+ * relative index within the respective arrays that is the length of the
+ * prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(byte[], int, int, byte[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Byte.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is null
+ * @since 9
+ */
+ public static int compareUnsigned(byte[] a, int aFromIndex, int aToIndex,
+ byte[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ byte va = a[aFromIndex++];
+ byte vb = b[bFromIndex++];
+ if (va != vb) return Byte.compareUnsigned(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ // Compare short
+
+ /**
+ * Compares two {@code short} arrays lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Short#compare(short, short)}, at an index within the respective
+ * arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(short[], short[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(short[], short[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Short.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compare(short[] a, short[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Short.compare(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code short} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Short#compare(short, short)}, at a relative
+ * index within the respective arrays that is the length of the prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(short[], int, int, short[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(short[], int, int, short[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Short.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int compare(short[] a, int aFromIndex, int aToIndex,
+ short[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ short va = a[aFromIndex++];
+ short vb = b[bFromIndex++];
+ if (va != vb) return Short.compare(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ /**
+ * Compares two {@code short} arrays lexicographically, numerically treating
+ * elements as unsigned.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Short#compareUnsigned(short, short)}, at an index within the
+ * respective arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(short[], short[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Short.compareUnsigned(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are
+ * equal and contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compareUnsigned(short[] a, short[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Short.compareUnsigned(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code short} arrays lexicographically over the specified
+ * ranges, numerically treating elements as unsigned.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Short#compareUnsigned(short, short)}, at a
+ * relative index within the respective arrays that is the length of the
+ * prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(short[], int, int, short[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Short.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is null
+ * @since 9
+ */
+ public static int compareUnsigned(short[] a, int aFromIndex, int aToIndex,
+ short[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ short va = a[aFromIndex++];
+ short vb = b[bFromIndex++];
+ if (va != vb) return Short.compareUnsigned(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ // Compare char
+
+ /**
+ * Compares two {@code char} arrays lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Character#compare(char, char)}, at an index within the respective
+ * arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(char[], char[])} for the definition of a common and
+ * proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(char[], char[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Character.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compare(char[] a, char[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Character.compare(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code char} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Character#compare(char, char)}, at a relative
+ * index within the respective arrays that is the length of the prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(char[], int, int, char[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(char[], int, int, char[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Character.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int compare(char[] a, int aFromIndex, int aToIndex,
+ char[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ char va = a[aFromIndex++];
+ char vb = b[bFromIndex++];
+ if (va != vb) return Character.compare(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ // Compare int
+
+ /**
+ * Compares two {@code int} arrays lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Integer#compare(int, int)}, at an index within the respective
+ * arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(int[], int[])} for the definition of a common and
+ * proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(int[], int[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Integer.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compare(int[] a, int[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Integer.compare(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code int} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Integer#compare(int, int)}, at a relative index
+ * within the respective arrays that is the length of the prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(int[], int, int, int[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(int[], int, int, int[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Integer.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int compare(int[] a, int aFromIndex, int aToIndex,
+ int[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ int va = a[aFromIndex++];
+ int vb = b[bFromIndex++];
+ if (va != vb) return Integer.compare(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ /**
+ * Compares two {@code int} arrays lexicographically, numerically treating
+ * elements as unsigned.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Integer#compareUnsigned(int, int)}, at an index within the
+ * respective arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(int[], int[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Integer.compareUnsigned(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are
+ * equal and contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compareUnsigned(int[] a, int[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Integer.compareUnsigned(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code int} arrays lexicographically over the specified
+ * ranges, numerically treating elements as unsigned.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Integer#compareUnsigned(int, int)}, at a
+ * relative index within the respective arrays that is the length of the
+ * prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(int[], int, int, int[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Integer.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is null
+ * @since 9
+ */
+ public static int compareUnsigned(int[] a, int aFromIndex, int aToIndex,
+ int[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ int va = a[aFromIndex++];
+ int vb = b[bFromIndex++];
+ if (va != vb) return Integer.compareUnsigned(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ // Compare long
+
+ /**
+ * Compares two {@code long} arrays lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Long#compare(long, long)}, at an index within the respective
+ * arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(long[], long[])} for the definition of a common and
+ * proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(long[], long[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Long.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compare(long[] a, long[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Long.compare(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code long} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Long#compare(long, long)}, at a relative index
+ * within the respective arrays that is the length of the prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(long[], int, int, long[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(long[], int, int, long[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Long.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int compare(long[] a, int aFromIndex, int aToIndex,
+ long[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ long va = a[aFromIndex++];
+ long vb = b[bFromIndex++];
+ if (va != vb) return Long.compare(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ /**
+ * Compares two {@code long} arrays lexicographically, numerically treating
+ * elements as unsigned.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Long#compareUnsigned(long, long)}, at an index within the
+ * respective arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(long[], long[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Long.compareUnsigned(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are
+ * equal and contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compareUnsigned(long[] a, long[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return Long.compareUnsigned(a[i], b[i]);
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code long} arrays lexicographically over the specified
+ * ranges, numerically treating elements as unsigned.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Long#compareUnsigned(long, long)}, at a
+ * relative index within the respective arrays that is the length of the
+ * prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(long[], int, int, long[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Long.compareUnsigned(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is null
+ * @since 9
+ */
+ public static int compareUnsigned(long[] a, int aFromIndex, int aToIndex,
+ long[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ long va = a[aFromIndex++];
+ long vb = b[bFromIndex++];
+ if (va != vb) return Long.compareUnsigned(va, vb);
+ }
+
+ return aLength - bLength;
+ }
+
+ // Compare float
+
+ /**
+ * Compares two {@code float} arrays lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Float#compare(float, float)}, at an index within the respective
+ * arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(float[], float[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(float[], float[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Float.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compare(float[] a, float[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ float va = a[i], vb = b[i];
+ if (Float.floatToRawIntBits(va) != Float.floatToRawIntBits(vb)) {
+ int c = Float.compare(va, vb);
+ if (c != 0) return c;
+ }
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code float} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Float#compare(float, float)}, at a relative
+ * index within the respective arrays that is the length of the prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(float[], int, int, float[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(float[], int, int, float[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Float.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int compare(float[] a, int aFromIndex, int aToIndex,
+ float[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ float va = a[aFromIndex++], vb = b[bFromIndex++];
+ if (Float.floatToRawIntBits(va) != Float.floatToRawIntBits(vb)) {
+ int c = Float.compare(va, vb);
+ if (c != 0) return c;
+ }
+ }
+
+ return aLength - bLength;
+ }
+
+ // Compare double
+
+ /**
+ * Compares two {@code double} arrays lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements, as if by
+ * {@link Double#compare(double, double)}, at an index within the respective
+ * arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(double[], double[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(double[], double[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return Double.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static int compare(double[] a, double[] b) {
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ double va = a[i], vb = b[i];
+ if (Double.doubleToRawLongBits(va) != Double.doubleToRawLongBits(vb)) {
+ int c = Double.compare(va, vb);
+ if (c != 0) return c;
+ }
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code double} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements, as if by {@link Double#compare(double, double)}, at a relative
+ * index within the respective arrays that is the length of the prefix.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(double[], int, int, double[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(double[], int, int, double[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if:
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return Double.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int compare(double[] a, int aFromIndex, int aToIndex,
+ double[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ double va = a[aFromIndex++], vb = b[bFromIndex++];
+ if (Double.doubleToRawLongBits(va) != Double.doubleToRawLongBits(vb)) {
+ int c = Double.compare(va, vb);
+ if (c != 0) return c;
+ }
+ }
+
+ return aLength - bLength;
+ }
+
+ // Compare objects
+
+ /**
+ * Compares two {@code Object} arrays, within comparable elements,
+ * lexicographically.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing two elements of type {@code T} at
+ * an index {@code i} within the respective arrays that is the prefix
+ * length, as if by:
+ * <pre>{@code
+ * Comparator.nullsFirst(Comparator.<T>naturalOrder()).
+ * compare(a[i], b[i])
+ * }</pre>
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(Object[], Object[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ * A {@code null} array element is considered lexicographically than a
+ * non-{@code null} array element. Two {@code null} array elements are
+ * considered equal.
+ *
+ * <p>The comparison is consistent with {@link #equals(Object[], Object[]) equals},
+ * more specifically the following holds for arrays {@code a} and {@code b}:
+ * <pre>{@code
+ * Arrays.equals(a, b) == (Arrays.compare(a, b) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references
+ * and elements):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return a[i].compareTo(b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @param <T> the type of comparable array elements
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @since 9
+ */
+ public static <T extends Comparable<? super T>> int compare(T[] a, T[] b) {
+ if (a == b)
+ return 0;
+ // A null array is less than a non-null array
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ T oa = a[i];
+ T ob = b[i];
+ if (oa != ob) {
+ // A null element is less than a non-null element
+ if (oa == null || ob == null)
+ return oa == null ? -1 : 1;
+ int v = oa.compareTo(ob);
+ if (v != 0) {
+ return v;
+ }
+ }
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code Object} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing two
+ * elements of type {@code T} at a relative index {@code i} within the
+ * respective arrays that is the prefix length, as if by:
+ * <pre>{@code
+ * Comparator.nullsFirst(Comparator.<T>naturalOrder()).
+ * compare(a[aFromIndex + i, b[bFromIndex + i])
+ * }</pre>
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(Object[], int, int, Object[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * <p>The comparison is consistent with
+ * {@link #equals(Object[], int, int, Object[], int, int) equals}, more
+ * specifically the following holds for arrays {@code a} and {@code b} with
+ * specified ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively:
+ * <pre>{@code
+ * Arrays.equals(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) ==
+ * (Arrays.compare(a, aFromIndex, aToIndex, b, bFromIndex, bToIndex) == 0)
+ * }</pre>
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array elements):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return a[aFromIndex + i].compareTo(b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @param <T> the type of comparable array elements
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static <T extends Comparable<? super T>> int compare(
+ T[] a, int aFromIndex, int aToIndex,
+ T[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ T oa = a[aFromIndex++];
+ T ob = b[bFromIndex++];
+ if (oa != ob) {
+ if (oa == null || ob == null)
+ return oa == null ? -1 : 1;
+ int v = oa.compareTo(ob);
+ if (v != 0) {
+ return v;
+ }
+ }
+ }
+
+ return aLength - bLength;
+ }
+
+ /**
+ * Compares two {@code Object} arrays lexicographically using a specified
+ * comparator.
+ *
+ * <p>If the two arrays share a common prefix then the lexicographic
+ * comparison is the result of comparing with the specified comparator two
+ * elements at an index within the respective arrays that is the prefix
+ * length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two array lengths.
+ * (See {@link #mismatch(Object[], Object[])} for the definition of a common
+ * and proper prefix.)
+ *
+ * <p>A {@code null} array reference is considered lexicographically less
+ * than a non-{@code null} array reference. Two {@code null} array
+ * references are considered equal.
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array references):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, b, cmp);
+ * if (i >= 0 && i < Math.min(a.length, b.length))
+ * return cmp.compare(a[i], b[i]);
+ * return a.length - b.length;
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param b the second array to compare
+ * @param cmp the comparator to compare array elements
+ * @param <T> the type of array elements
+ * @return the value {@code 0} if the first and second array are equal and
+ * contain the same elements in the same order;
+ * a value less than {@code 0} if the first array is
+ * lexicographically less than the second array; and
+ * a value greater than {@code 0} if the first array is
+ * lexicographically greater than the second array
+ * @throws NullPointerException if the comparator is {@code null}
+ * @since 9
+ */
+ public static <T> int compare(T[] a, T[] b,
+ Comparator<? super T> cmp) {
+ Objects.requireNonNull(cmp);
+ if (a == b)
+ return 0;
+ if (a == null || b == null)
+ return a == null ? -1 : 1;
+
+ int length = Math.min(a.length, b.length);
+ for (int i = 0; i < length; i++) {
+ T oa = a[i];
+ T ob = b[i];
+ if (oa != ob) {
+ // Null-value comparison is deferred to the comparator
+ int v = cmp.compare(oa, ob);
+ if (v != 0) {
+ return v;
+ }
+ }
+ }
+
+ return a.length - b.length;
+ }
+
+ /**
+ * Compares two {@code Object} arrays lexicographically over the specified
+ * ranges.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the lexicographic comparison is the result of comparing with the
+ * specified comparator two elements at a relative index within the
+ * respective arrays that is the prefix length.
+ * Otherwise, one array is a proper prefix of the other and, lexicographic
+ * comparison is the result of comparing the two range lengths.
+ * (See {@link #mismatch(Object[], int, int, Object[], int, int)} for the
+ * definition of a common and proper prefix.)
+ *
+ * @apiNote
+ * <p>This method behaves as if (for non-{@code null} array elements):
+ * <pre>{@code
+ * int i = Arrays.mismatch(a, aFromIndex, aToIndex,
+ * b, bFromIndex, bToIndex, cmp);
+ * if (i >= 0 && i < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * return cmp.compare(a[aFromIndex + i], b[bFromIndex + i]);
+ * return (aToIndex - aFromIndex) - (bToIndex - bFromIndex);
+ * }</pre>
+ *
+ * @param a the first array to compare
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be compared
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be compared
+ * @param b the second array to compare
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be compared
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be compared
+ * @param cmp the comparator to compare array elements
+ * @param <T> the type of array elements
+ * @return the value {@code 0} if, over the specified ranges, the first and
+ * second array are equal and contain the same elements in the same
+ * order;
+ * a value less than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically less than the second array; and
+ * a value greater than {@code 0} if, over the specified ranges, the
+ * first array is lexicographically greater than the second array
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array or the comparator is {@code null}
+ * @since 9
+ */
+ public static <T> int compare(
+ T[] a, int aFromIndex, int aToIndex,
+ T[] b, int bFromIndex, int bToIndex,
+ Comparator<? super T> cmp) {
+ Objects.requireNonNull(cmp);
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ T oa = a[aFromIndex++];
+ T ob = b[bFromIndex++];
+ if (oa != ob) {
+ // Null-value comparison is deferred to the comparator
+ int v = cmp.compare(oa, ob);
+ if (v != 0) {
+ return v;
+ }
+ }
+ }
+
+ return aLength - bLength;
+ }
+
+
+ // Mismatch methods
+
+ // Mismatch boolean
+
+ /**
+ * Finds and returns the index of the first mismatch between two
+ * {@code boolean} arrays, otherwise return -1 if no mismatch is found. The
+ * index will be in the range of 0 (inclusive) up to the length (inclusive)
+ * of the smaller array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * a[pl] != b[pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(boolean[] a, boolean[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code boolean} arrays over the specified ranges, otherwise return -1 if
+ * no mismatch is found. The index will be in the range of 0 (inclusive) up
+ * to the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * a[aFromIndex + pl] != b[bFromIndex + pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(boolean[] a, int aFromIndex, int aToIndex,
+ boolean[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ if (a[aFromIndex++] != b[bFromIndex++]) return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ // Mismatch byte
+
+ /**
+ * Finds and returns the index of the first mismatch between two {@code byte}
+ * arrays, otherwise return -1 if no mismatch is found. The index will be
+ * in the range of 0 (inclusive) up to the length (inclusive) of the smaller
+ * array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * a[pl] != b[pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(byte[] a, byte[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code byte} arrays over the specified ranges, otherwise return -1 if no
+ * mismatch is found. The index will be in the range of 0 (inclusive) up to
+ * the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * a[aFromIndex + pl] != b[bFromIndex + pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(byte[] a, int aFromIndex, int aToIndex,
+ byte[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ if (a[aFromIndex++] != b[bFromIndex++]) return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ // Mismatch char
+
+ /**
+ * Finds and returns the index of the first mismatch between two {@code char}
+ * arrays, otherwise return -1 if no mismatch is found. The index will be
+ * in the range of 0 (inclusive) up to the length (inclusive) of the smaller
+ * array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * a[pl] != b[pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(char[] a, char[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code char} arrays over the specified ranges, otherwise return -1 if no
+ * mismatch is found. The index will be in the range of 0 (inclusive) up to
+ * the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * a[aFromIndex + pl] != b[bFromIndex + pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(char[] a, int aFromIndex, int aToIndex,
+ char[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ if (a[aFromIndex++] != b[bFromIndex++]) return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ // Mismatch short
+
+ /**
+ * Finds and returns the index of the first mismatch between two {@code short}
+ * arrays, otherwise return -1 if no mismatch is found. The index will be
+ * in the range of 0 (inclusive) up to the length (inclusive) of the smaller
+ * array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * a[pl] != b[pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(short[] a, short[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code short} arrays over the specified ranges, otherwise return -1 if no
+ * mismatch is found. The index will be in the range of 0 (inclusive) up to
+ * the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * a[aFromIndex + pl] != b[bFromIndex + pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(short[] a, int aFromIndex, int aToIndex,
+ short[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ if (a[aFromIndex++] != b[bFromIndex++]) return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ // Mismatch int
+
+ /**
+ * Finds and returns the index of the first mismatch between two {@code int}
+ * arrays, otherwise return -1 if no mismatch is found. The index will be
+ * in the range of 0 (inclusive) up to the length (inclusive) of the smaller
+ * array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * a[pl] != b[pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(int[] a, int[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code int} arrays over the specified ranges, otherwise return -1 if no
+ * mismatch is found. The index will be in the range of 0 (inclusive) up to
+ * the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * a[aFromIndex + pl] != b[bFromIndex + pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(int[] a, int aFromIndex, int aToIndex,
+ int[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ if (a[aFromIndex++] != b[bFromIndex++]) return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ // Mismatch long
+
+ /**
+ * Finds and returns the index of the first mismatch between two {@code long}
+ * arrays, otherwise return -1 if no mismatch is found. The index will be
+ * in the range of 0 (inclusive) up to the length (inclusive) of the smaller
+ * array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * a[pl] != b[pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(long[] a, long[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ if (a[i] != b[i]) return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code long} arrays over the specified ranges, otherwise return -1 if no
+ * mismatch is found. The index will be in the range of 0 (inclusive) up to
+ * the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * a[aFromIndex + pl] != b[bFromIndex + pl]
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(long[] a, int aFromIndex, int aToIndex,
+ long[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ if (a[aFromIndex++] != b[bFromIndex++]) return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ // Mismatch float
+
+ /**
+ * Finds and returns the index of the first mismatch between two {@code float}
+ * arrays, otherwise return -1 if no mismatch is found. The index will be
+ * in the range of 0 (inclusive) up to the length (inclusive) of the smaller
+ * array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * Float.compare(a[pl], b[pl]) != 0
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(float[] a, float[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ float va = a[i], vb = b[i];
+ if (Float.floatToRawIntBits(va) != Float.floatToRawIntBits(vb))
+ if (!Float.isNaN(va) || !Float.isNaN(vb))
+ return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code float} arrays over the specified ranges, otherwise return -1 if no
+ * mismatch is found. The index will be in the range of 0 (inclusive) up to
+ * the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * Float.compare(a[aFromIndex + pl], b[bFromIndex + pl]) != 0
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(float[] a, int aFromIndex, int aToIndex,
+ float[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ float va = a[aFromIndex++], vb = b[bFromIndex++];
+ if (Float.floatToRawIntBits(va) != Float.floatToRawIntBits(vb))
+ if (!Float.isNaN(va) || !Float.isNaN(vb))
+ return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ // Mismatch double
+
+ /**
+ * Finds and returns the index of the first mismatch between two
+ * {@code double} arrays, otherwise return -1 if no mismatch is found. The
+ * index will be in the range of 0 (inclusive) up to the length (inclusive)
+ * of the smaller array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * Double.compare(a[pl], b[pl]) != 0
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(double[] a, double[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ double va = a[i], vb = b[i];
+ if (Double.doubleToRawLongBits(va) != Double.doubleToRawLongBits(vb))
+ if (!Double.isNaN(va) || !Double.isNaN(vb))
+ return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code double} arrays over the specified ranges, otherwise return -1 if
+ * no mismatch is found. The index will be in the range of 0 (inclusive) up
+ * to the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * Double.compare(a[aFromIndex + pl], b[bFromIndex + pl]) != 0
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(double[] a, int aFromIndex, int aToIndex,
+ double[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ double va = a[aFromIndex++], vb = b[bFromIndex++];
+ if (Double.doubleToRawLongBits(va) != Double.doubleToRawLongBits(vb))
+ if (!Double.isNaN(va) || !Double.isNaN(vb))
+ return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ // Mismatch objects
+
+ /**
+ * Finds and returns the index of the first mismatch between two
+ * {@code Object} arrays, otherwise return -1 if no mismatch is found. The
+ * index will be in the range of 0 (inclusive) up to the length (inclusive)
+ * of the smaller array.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * Arrays.equals(a, 0, pl, b, 0, pl) &&
+ * !Objects.equals(a[pl], b[pl])
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * Arrays.equals(a, 0, Math.min(a.length, b.length),
+ * b, 0, Math.min(a.length, b.length))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(Object[] a, Object[] b) {
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ if (!Objects.equals(a[i], b[i]))
+ return i;
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code Object} arrays over the specified ranges, otherwise return -1 if
+ * no mismatch is found. The index will be in the range of 0 (inclusive) up
+ * to the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * Arrays.equals(a, aFromIndex, aFromIndex + pl, b, bFromIndex, bFromIndex + pl) &&
+ * !Objects.equals(a[aFromIndex + pl], b[bFromIndex + pl])
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * Arrays.equals(a, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex),
+ * b, 0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex))
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array is {@code null}
+ * @since 9
+ */
+ public static int mismatch(
+ Object[] a, int aFromIndex, int aToIndex,
+ Object[] b, int bFromIndex, int bToIndex) {
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ if (!Objects.equals(a[aFromIndex++], b[bFromIndex++]))
+ return i;
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+
+ /**
+ * Finds and returns the index of the first mismatch between two
+ * {@code Object} arrays, otherwise return -1 if no mismatch is found.
+ * The index will be in the range of 0 (inclusive) up to the length
+ * (inclusive) of the smaller array.
+ *
+ * <p>The specified comparator is used to determine if two array elements
+ * from the each array are not equal.
+ *
+ * <p>If the two arrays share a common prefix then the returned index is the
+ * length of the common prefix and it follows that there is a mismatch
+ * between the two elements at that index within the respective arrays.
+ * If one array is a proper prefix of the other then the returned index is
+ * the length of the smaller array and it follows that the index is only
+ * valid for the larger array.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(a.length, b.length) &&
+ * IntStream.range(0, pl).
+ * map(i -> cmp.compare(a[i], b[i])).
+ * allMatch(c -> c == 0) &&
+ * cmp.compare(a[pl], b[pl]) != 0
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b}, share a proper
+ * prefix if the following expression is true:
+ * <pre>{@code
+ * a.length != b.length &&
+ * IntStream.range(0, Math.min(a.length, b.length)).
+ * map(i -> cmp.compare(a[i], b[i])).
+ * allMatch(c -> c == 0) &&
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param b the second array to be tested for a mismatch
+ * @param cmp the comparator to compare array elements
+ * @param <T> the type of array elements
+ * @return the index of the first mismatch between the two arrays,
+ * otherwise {@code -1}.
+ * @throws NullPointerException
+ * if either array or the comparator is {@code null}
+ * @since 9
+ */
+ public static <T> int mismatch(T[] a, T[] b, Comparator<? super T> cmp) {
+ Objects.requireNonNull(cmp);
+ int length = Math.min(a.length, b.length); // Check null array refs
+ if (a == b)
+ return -1;
+
+ for (int i = 0; i < length; i++) {
+ T oa = a[i];
+ T ob = b[i];
+ if (oa != ob) {
+ // Null-value comparison is deferred to the comparator
+ int v = cmp.compare(oa, ob);
+ if (v != 0) {
+ return i;
+ }
+ }
+ }
+
+ return a.length != b.length ? length : -1;
+ }
+
+ /**
+ * Finds and returns the relative index of the first mismatch between two
+ * {@code Object} arrays over the specified ranges, otherwise return -1 if
+ * no mismatch is found. The index will be in the range of 0 (inclusive) up
+ * to the length (inclusive) of the smaller range.
+ *
+ * <p>If the two arrays, over the specified ranges, share a common prefix
+ * then the returned relative index is the length of the common prefix and
+ * it follows that there is a mismatch between the two elements at that
+ * relative index within the respective arrays.
+ * If one array is a proper prefix of the other, over the specified ranges,
+ * then the returned relative index is the length of the smaller range and
+ * it follows that the relative index is only valid for the array with the
+ * larger range.
+ * Otherwise, there is no mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a common
+ * prefix of length {@code pl} if the following expression is true:
+ * <pre>{@code
+ * pl >= 0 &&
+ * pl < Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex) &&
+ * IntStream.range(0, pl).
+ * map(i -> cmp.compare(a[aFromIndex + i], b[bFromIndex + i])).
+ * allMatch(c -> c == 0) &&
+ * cmp.compare(a[aFromIndex + pl], b[bFromIndex + pl]) != 0
+ * }</pre>
+ * Note that a common prefix length of {@code 0} indicates that the first
+ * elements from each array mismatch.
+ *
+ * <p>Two non-{@code null} arrays, {@code a} and {@code b} with specified
+ * ranges [{@code aFromIndex}, {@code atoIndex}) and
+ * [{@code bFromIndex}, {@code btoIndex}) respectively, share a proper
+ * if the following expression is true:
+ * <pre>{@code
+ * (aToIndex - aFromIndex) != (bToIndex - bFromIndex) &&
+ * IntStream.range(0, Math.min(aToIndex - aFromIndex, bToIndex - bFromIndex)).
+ * map(i -> cmp.compare(a[aFromIndex + i], b[bFromIndex + i])).
+ * allMatch(c -> c == 0)
+ * }</pre>
+ *
+ * @param a the first array to be tested for a mismatch
+ * @param aFromIndex the index (inclusive) of the first element in the
+ * first array to be tested
+ * @param aToIndex the index (exclusive) of the last element in the
+ * first array to be tested
+ * @param b the second array to be tested for a mismatch
+ * @param bFromIndex the index (inclusive) of the first element in the
+ * second array to be tested
+ * @param bToIndex the index (exclusive) of the last element in the
+ * second array to be tested
+ * @param cmp the comparator to compare array elements
+ * @param <T> the type of array elements
+ * @return the relative index of the first mismatch between the two arrays
+ * over the specified ranges, otherwise {@code -1}.
+ * @throws IllegalArgumentException
+ * if {@code aFromIndex > aToIndex} or
+ * if {@code bFromIndex > bToIndex}
+ * @throws ArrayIndexOutOfBoundsException
+ * if {@code aFromIndex < 0 or aToIndex > a.length} or
+ * if {@code bFromIndex < 0 or bToIndex > b.length}
+ * @throws NullPointerException
+ * if either array or the comparator is {@code null}
+ * @since 9
+ */
+ public static <T> int mismatch(
+ T[] a, int aFromIndex, int aToIndex,
+ T[] b, int bFromIndex, int bToIndex,
+ Comparator<? super T> cmp) {
+ Objects.requireNonNull(cmp);
+ rangeCheck(a.length, aFromIndex, aToIndex);
+ rangeCheck(b.length, bFromIndex, bToIndex);
+
+ int aLength = aToIndex - aFromIndex;
+ int bLength = bToIndex - bFromIndex;
+ int length = Math.min(aLength, bLength);
+ for (int i = 0; i < length; i++) {
+ T oa = a[aFromIndex++];
+ T ob = b[bFromIndex++];
+ if (oa != ob) {
+ // Null-value comparison is deferred to the comparator
+ int v = cmp.compare(oa, ob);
+ if (v != 0) {
+ return i;
+ }
+ }
+ }
+
+ return aLength != bLength ? length : -1;
+ }
+}
\ No newline at end of file