/*

 * Copyright (c) 2014, Oracle and/or its affiliates. All rights reserved.

 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.

 *

 * This code is free software; you can redistribute it and/or modify it

 * under the terms of the GNU General Public License version 2 only, as

 * published by the Free Software Foundation.

 *

 * This code is distributed in the hope that it will be useful, but WITHOUT

 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or

 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License

 * version 2 for more details (a copy is included in the LICENSE file that

 * accompanied this code).

 *

 * You should have received a copy of the GNU General Public License version

 * 2 along with this work; if not, write to the Free Software Foundation,

 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.

 *

 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA

 * or visit www.oracle.com if you need additional information or have any

 * questions.

 */

/*

 * @test

 * @bug 8055910

 * @summary Arrays.copyOf doesn't perform subtype check

 * @run main/othervm -XX:-BackgroundCompilation -XX:-UseOnStackReplacement TestArrayOfNoTypeCheck

 *

 */

import java.util.Arrays;

public class TestArrayOfNoTypeCheck {

    static class A {

    }

    static class B extends A {

    }

    static B[] test(A[] arr) {

        return Arrays.copyOf(arr, 10, B[].class);

    }

    static public void main(String[] args) {

        A[] arr = new A[20];

        for (int i = 0; i < 20000; i++) {

            test(arr);

        }

        A[] arr2 = new A[20];

        arr2[0] = new A();

        boolean exception = false;

        try {

            test(arr2);

        } catch (ArrayStoreException ase) {

            exception = true;

        }

        if (!exception) {

            throw new RuntimeException("TEST FAILED: ArrayStoreException not thrown");

        }

    }

}