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/*
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* reserved comment block
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* DO NOT REMOVE OR ALTER!
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*/
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package com.sun.org.apache.bcel.internal.generic;
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/* ====================================================================
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* The Apache Software License, Version 1.1
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*
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* Copyright (c) 2001 The Apache Software Foundation. All rights
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* reserved.
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*
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* Redistribution and use in source and binary forms, with or without
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* modification, are permitted provided that the following conditions
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* are met:
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*
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* 1. Redistributions of source code must retain the above copyright
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* notice, this list of conditions and the following disclaimer.
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*
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* 2. Redistributions in binary form must reproduce the above copyright
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* notice, this list of conditions and the following disclaimer in
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* the documentation and/or other materials provided with the
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* distribution.
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*
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* 3. The end-user documentation included with the redistribution,
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* if any, must include the following acknowledgment:
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* "This product includes software developed by the
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* Apache Software Foundation (http://www.apache.org/)."
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* Alternately, this acknowledgment may appear in the software itself,
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* if and wherever such third-party acknowledgments normally appear.
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*
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* 4. The names "Apache" and "Apache Software Foundation" and
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* "Apache BCEL" must not be used to endorse or promote products
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* derived from this software without prior written permission. For
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* written permission, please contact apache@apache.org.
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*
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* 5. Products derived from this software may not be called "Apache",
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* "Apache BCEL", nor may "Apache" appear in their name, without
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* prior written permission of the Apache Software Foundation.
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*
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* THIS SOFTWARE IS PROVIDED ``AS IS'' AND ANY EXPRESSED OR IMPLIED
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* WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
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* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
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* DISCLAIMED. IN NO EVENT SHALL THE APACHE SOFTWARE FOUNDATION OR
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* ITS CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
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* SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
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* LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF
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* USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND
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* ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY,
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* OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT
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* OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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* SUCH DAMAGE.
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* ====================================================================
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*
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* This software consists of voluntary contributions made by many
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* individuals on behalf of the Apache Software Foundation. For more
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* information on the Apache Software Foundation, please see
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* <http://www.apache.org/>.
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*/
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import com.sun.org.apache.bcel.internal.Constants;
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import com.sun.org.apache.bcel.internal.Repository;
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import com.sun.org.apache.bcel.internal.classfile.JavaClass;
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/**
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* Super class for object and array types.
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*
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* @author <A HREF="mailto:markus.dahm@berlin.de">M. Dahm</A>
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*/
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public abstract class ReferenceType extends Type {
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protected ReferenceType(byte t, String s) {
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super(t, s);
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}
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/** Class is non-abstract but not instantiable from the outside
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*/
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ReferenceType() {
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super(Constants.T_OBJECT, "<null object>");
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}
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/**
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* Return true iff this type is castable to another type t as defined in
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* the JVM specification. The case where this is Type.NULL is not
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* defined (see the CHECKCAST definition in the JVM specification).
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* However, because e.g. CHECKCAST doesn't throw a
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* ClassCastException when casting a null reference to any Object,
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* true is returned in this case.
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*/
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public boolean isCastableTo(Type t) {
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if (this.equals(Type.NULL))
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return true; // If this is ever changed in isAssignmentCompatible()
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return isAssignmentCompatibleWith(t);
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/* Yes, it's true: It's the same definition.
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* See vmspec2 AASTORE / CHECKCAST definitions.
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*/
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}
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/**
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* Return true iff this is assignment compatible with another type t
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* as defined in the JVM specification; see the AASTORE definition
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* there.
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*/
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public boolean isAssignmentCompatibleWith(Type t) {
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if (!(t instanceof ReferenceType))
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return false;
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ReferenceType T = (ReferenceType) t;
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if (this.equals(Type.NULL))
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return true; // This is not explicitely stated, but clear. Isn't it?
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/* If this is a class type then
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*/
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if ((this instanceof ObjectType) && (((ObjectType) this).referencesClass())) {
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/* If T is a class type, then this must be the same class as T,
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or this must be a subclass of T;
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*/
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if ((T instanceof ObjectType) && (((ObjectType) T).referencesClass())) {
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if (this.equals(T))
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return true;
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if (Repository.instanceOf(((ObjectType) this).getClassName(),
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((ObjectType) T).getClassName()))
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return true;
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}
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/* If T is an interface type, this must implement interface T.
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*/
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if ((T instanceof ObjectType) && (((ObjectType) T).referencesInterface())) {
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if (Repository.implementationOf(((ObjectType) this).getClassName(),
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((ObjectType) T).getClassName()))
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return true;
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}
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}
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/* If this is an interface type, then:
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*/
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if ((this instanceof ObjectType) && (((ObjectType) this).referencesInterface())) {
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/* If T is a class type, then T must be Object (2.4.7).
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*/
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if ((T instanceof ObjectType) && (((ObjectType) T).referencesClass())) {
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if (T.equals(Type.OBJECT)) return true;
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}
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/* If T is an interface type, then T must be the same interface
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* as this or a superinterface of this (2.13.2).
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*/
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if ((T instanceof ObjectType) && (((ObjectType) T).referencesInterface())) {
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if (this.equals(T)) return true;
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if (Repository.implementationOf(((ObjectType) this).getClassName(),
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((ObjectType) T).getClassName()))
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return true;
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}
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}
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/* If this is an array type, namely, the type SC[], that is, an
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* array of components of type SC, then:
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*/
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if (this instanceof ArrayType) {
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/* If T is a class type, then T must be Object (2.4.7).
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*/
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if ((T instanceof ObjectType) && (((ObjectType) T).referencesClass())) {
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if (T.equals(Type.OBJECT)) return true;
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}
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/* If T is an array type TC[], that is, an array of components
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* of type TC, then one of the following must be true:
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*/
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if (T instanceof ArrayType) {
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/* TC and SC are the same primitive type (2.4.1).
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*/
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Type sc = ((ArrayType) this).getElementType();
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Type tc = ((ArrayType) this).getElementType();
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if (sc instanceof BasicType && tc instanceof BasicType && sc.equals(tc))
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return true;
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/* TC and SC are reference types (2.4.6), and type SC is
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* assignable to TC by these runtime rules.
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*/
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if (tc instanceof ReferenceType && sc instanceof ReferenceType &&
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((ReferenceType) sc).isAssignmentCompatibleWith((ReferenceType) tc))
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return true;
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}
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/* If T is an interface type, T must be one of the interfaces implemented by arrays (2.15). */
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// TODO: Check if this is still valid or find a way to dynamically find out which
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// interfaces arrays implement. However, as of the JVM specification edition 2, there
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// are at least two different pages where assignment compatibility is defined and
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// on one of them "interfaces implemented by arrays" is exchanged with "'Cloneable' or
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// 'java.io.Serializable'"
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if ((T instanceof ObjectType) && (((ObjectType) T).referencesInterface())) {
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for (int ii = 0; ii < Constants.INTERFACES_IMPLEMENTED_BY_ARRAYS.length; ii++) {
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if (T.equals(new ObjectType(Constants.INTERFACES_IMPLEMENTED_BY_ARRAYS[ii]))) return true;
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}
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}
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}
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return false; // default.
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}
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/**
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* This commutative operation returns the first common superclass (narrowest ReferenceType
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* referencing a class, not an interface).
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* If one of the types is a superclass of the other, the former is returned.
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* If "this" is Type.NULL, then t is returned.
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* If t is Type.NULL, then "this" is returned.
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* If "this" equals t ['this.equals(t)'] "this" is returned.
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* If "this" or t is an ArrayType, then Type.OBJECT is returned;
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* unless their dimensions match. Then an ArrayType of the same
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* number of dimensions is returned, with its basic type being the
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* first common super class of the basic types of "this" and t.
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* If "this" or t is a ReferenceType referencing an interface, then Type.OBJECT is returned.
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* If not all of the two classes' superclasses cannot be found, "null" is returned.
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* See the JVM specification edition 2, "4.9.2 The Bytecode Verifier".
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*/
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public ReferenceType getFirstCommonSuperclass(ReferenceType t) {
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if (this.equals(Type.NULL)) return t;
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if (t.equals(Type.NULL)) return this;
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if (this.equals(t)) return this;
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/*
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* TODO: Above sounds a little arbitrary. On the other hand, there is
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* no object referenced by Type.NULL so we can also say all the objects
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* referenced by Type.NULL were derived from java.lang.Object.
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* However, the Java Language's "instanceof" operator proves us wrong:
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* "null" is not referring to an instance of java.lang.Object :)
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*/
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/* This code is from a bug report by Konstantin Shagin <konst@cs.technion.ac.il> */
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if ((this instanceof ArrayType) && (t instanceof ArrayType)) {
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ArrayType arrType1 = (ArrayType) this;
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ArrayType arrType2 = (ArrayType) t;
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if (
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(arrType1.getDimensions() == arrType2.getDimensions()) &&
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arrType1.getBasicType() instanceof ObjectType &&
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arrType2.getBasicType() instanceof ObjectType) {
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return new ArrayType(
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((ObjectType) arrType1.getBasicType()).getFirstCommonSuperclass((ObjectType) arrType2.getBasicType()),
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arrType1.getDimensions()
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);
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}
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}
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if ((this instanceof ArrayType) || (t instanceof ArrayType))
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return Type.OBJECT;
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// TODO: Is there a proof of OBJECT being the direct ancestor of every ArrayType?
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if (((this instanceof ObjectType) && ((ObjectType) this).referencesInterface()) ||
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((t instanceof ObjectType) && ((ObjectType) t).referencesInterface()))
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return Type.OBJECT;
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// TODO: The above line is correct comparing to the vmspec2. But one could
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// make class file verification a bit stronger here by using the notion of
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// superinterfaces or even castability or assignment compatibility.
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// this and t are ObjectTypes, see above.
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ObjectType thiz = (ObjectType) this;
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ObjectType other = (ObjectType) t;
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JavaClass[] thiz_sups = Repository.getSuperClasses(thiz.getClassName());
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JavaClass[] other_sups = Repository.getSuperClasses(other.getClassName());
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if ((thiz_sups == null) || (other_sups == null)) {
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return null;
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}
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// Waaahh...
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JavaClass[] this_sups = new JavaClass[thiz_sups.length + 1];
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JavaClass[] t_sups = new JavaClass[other_sups.length + 1];
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System.arraycopy(thiz_sups, 0, this_sups, 1, thiz_sups.length);
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System.arraycopy(other_sups, 0, t_sups, 1, other_sups.length);
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this_sups[0] = Repository.lookupClass(thiz.getClassName());
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t_sups[0] = Repository.lookupClass(other.getClassName());
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for (int i = 0; i < t_sups.length; i++) {
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for (int j = 0; j < this_sups.length; j++) {
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if (this_sups[j].equals(t_sups[i])) return new ObjectType(this_sups[j].getClassName());
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}
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}
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// Huh? Did you ask for Type.OBJECT's superclass??
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return null;
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}
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/**
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* This commutative operation returns the first common superclass (narrowest ReferenceType
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* referencing a class, not an interface).
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* If one of the types is a superclass of the other, the former is returned.
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* If "this" is Type.NULL, then t is returned.
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* If t is Type.NULL, then "this" is returned.
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* If "this" equals t ['this.equals(t)'] "this" is returned.
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* If "this" or t is an ArrayType, then Type.OBJECT is returned.
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* If "this" or t is a ReferenceType referencing an interface, then Type.OBJECT is returned.
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* If not all of the two classes' superclasses cannot be found, "null" is returned.
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* See the JVM specification edition 2, "4.9.2 The Bytecode Verifier".
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*
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* @deprecated use getFirstCommonSuperclass(ReferenceType t) which has
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* slightly changed semantics.
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*/
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public ReferenceType firstCommonSuperclass(ReferenceType t) {
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if (this.equals(Type.NULL)) return t;
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if (t.equals(Type.NULL)) return this;
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if (this.equals(t)) return this;
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/*
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* TODO: Above sounds a little arbitrary. On the other hand, there is
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* no object referenced by Type.NULL so we can also say all the objects
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* referenced by Type.NULL were derived from java.lang.Object.
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* However, the Java Language's "instanceof" operator proves us wrong:
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* "null" is not referring to an instance of java.lang.Object :)
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*/
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if ((this instanceof ArrayType) || (t instanceof ArrayType))
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return Type.OBJECT;
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// TODO: Is there a proof of OBJECT being the direct ancestor of every ArrayType?
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if (((this instanceof ObjectType) && ((ObjectType) this).referencesInterface()) ||
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((t instanceof ObjectType) && ((ObjectType) t).referencesInterface()))
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return Type.OBJECT;
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// TODO: The above line is correct comparing to the vmspec2. But one could
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// make class file verification a bit stronger here by using the notion of
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// superinterfaces or even castability or assignment compatibility.
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// this and t are ObjectTypes, see above.
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ObjectType thiz = (ObjectType) this;
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ObjectType other = (ObjectType) t;
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JavaClass[] thiz_sups = Repository.getSuperClasses(thiz.getClassName());
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JavaClass[] other_sups = Repository.getSuperClasses(other.getClassName());
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if ((thiz_sups == null) || (other_sups == null)) {
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return null;
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}
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// Waaahh...
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JavaClass[] this_sups = new JavaClass[thiz_sups.length + 1];
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JavaClass[] t_sups = new JavaClass[other_sups.length + 1];
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System.arraycopy(thiz_sups, 0, this_sups, 1, thiz_sups.length);
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System.arraycopy(other_sups, 0, t_sups, 1, other_sups.length);
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this_sups[0] = Repository.lookupClass(thiz.getClassName());
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t_sups[0] = Repository.lookupClass(other.getClassName());
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for (int i = 0; i < t_sups.length; i++) {
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for (int j = 0; j < this_sups.length; j++) {
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if (this_sups[j].equals(t_sups[i])) return new ObjectType(this_sups[j].getClassName());
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}
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}
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// Huh? Did you ask for Type.OBJECT's superclass??
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return null;
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}
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}
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